flowchart RL
A[A at t1]
B[B at t2]
B e1@== remembers ==> A
e1@{ animate: true }
The Pennsylvania State University
npfomqg then type slide numberFor a full list of options, see Presenting Slides
Same psychology
If A is a person at time t1 and B is a person at t2, then B is the same person as A iff B at t2 has the same psychology as A at time t1.
Problems
Simple memory theory
If \(A\) is a person at time \(t_1\) and \(B\) is a person at \(t_2\), then \(B\) is the same person as A iff \(B\) at \(t_2\) has the memories of the experiences of \(A\) at time \(t_1\).
flowchart RL
A[A at t1]
B[B at t2]
B e1@== remembers ==> A
e1@{ animate: true }
Problem:
Occurrent memory
An occurrent memory is a memory someone is actively having.
Non-occurrent memory
A non-occurrent (dispositional) memory is a memory someone is capable of having.
Factual memory
A factual memory is a recollection of a fact about the world.
Procedural memory
A procedural memory is a memory of how to do something.
Personal (episodic) memory
A procedural memory is a memory about (1) an experience of an event but also (2) subjective information derived from the experience of that event.
Tek is actively remembering what he did yesterday.
Tek could remember his locker combination but right now he is solving a Rubik’s cube.
Tek remembers that Harrisburg is the capital of Pennsylvania.
Tek remembers that how excited he was when he was in Harrisburg.
Tek is solving the Rubik’s cube.
Genuine (strong) memory
Person \(A\) genuinely remembers doing event \(E\) only if \(A\) actually did \(E\).
Apparently (weak) memory
Person \(A\) apparently remembers doing event \(E\) only if \(A\) believes \(A\) did \(E\).
The claim that survival requires genuine memory is circular.
flowchart RL
R[A remembers B]
I["A=B"]
R <==> I
We need something that tells us when \(A=B\) but does not assume \(A=B\).
\(B\) having an apparent personal memory of \(A\) does not assume \(A=B\).
Simple memory theory (revised)
If \(A\) is a person at time \(t_1\) and \(B\) is a person at \(t_2\), then \(B\) is the same person as A iff \(B\) at \(t_2\) has the apparent personal memories of \(A\) at time \(t_1\).
Exercise
Create your own version of Reid’s famous objection.
Modified memory theory (MMT)
If \(A\) is a person at time \(t_1\) and \(B\) is a person at \(t_3\), then \(B\) is the same person as \(A\) iff either (i) \(B\) at \(t_3\) has an apparent non-occurrent memory of an experience of \(A\) at time \(t_1\) or (ii) there is some person \(C\) at \(t_2\) such that (a) \(B\) has an apparent non-occurrent memory of the experiences of \(C\) and (b) \(C\) has an apparent non-occurrent memory of the experiences of \(A\).
flowchart RL
A(A at t1)
C(C at t2)
B(B at t3)
B e1@== remembers ==> A
B e2@== remembers ==> C
C e3@== remembers ==> A
e1@{ animate: true }
e2@{ animate: true }
e3@{ animate: true }
There are periods of time when you have no apparent non-occurrent memory of the experiences of person \(A\) but you are person \(A\).
Suppose Charles in 2026 claims to be Guy Fawkes (1570-1606)
Suppose Liz claims to be Guy Fawkes (1570-1606)
Exercise
Create your own version of the Guy Fawkes fission objection.
Let’s try to fix the gaps problem with a new theory.
Psychological Connectedness Theory
If \(A\) is a person at time \(t_1\) and \(B\) is a person at \(t_3\), then \(B\) is the same person as \(A\) iff either
By psychological connectedness, we mean some weighted sum of psychological similarities or connections:
Psychological Connectedness Theory
Intuitively, Mary in Liverpool is the same person as the person in the plane as the person in Chicago even though there is a memory gap.
flowchart RL
A(A at t1)
B(B at t2)
C(C at t3)
C(D at t4)
C e1@== remembers ==> B
B e2@== remembers ==> A
B e2a@== psy conn ==> A
C e3@== psy conn ==> B
D e4@== psy conn ==> C
e1@{ animate: true }
e2@{ animate: true }
e2a@{ animate: true }
e3@{ animate: true }
e4@{ animate: true }
Suppose you are offered a free trip in the teletransportation device.
flowchart LR
A[Tek at t1]
B[Teletransporter]
C(Tek? at t2?)
A e1@== enters ==> B
B e2@== exits ==> C
e1@{ animate: true }
e2@{ animate: true }
Exercise
Would you use the teletransporter?
flowchart LR
C[Tek at Chicago]
T[Teletransporter]
P(Tek? in Paris)
V(Tek? in Vegas)
C e1@== enters ==> T
T e2@== exits ==> P
T e3@== exits ==> V
e1@{ animate: true }
e2@{ animate: true }
e3@{ animate: true }
Exercise
Two reasons to accept.
The problem with saying teletransportation (TT) is death is that there is no psychological difference between these two cases:
Psy theory needs to say what is the psychological difference. Physical theory might say that teletransportation results in death because of non-continuity of body.
non-branching condition
If \(A\) is a person at time \(t_1\) and \(B\) is a person at \(t_2\), then \(B=A\) iff there is psychological continuity between \(B\) and \(A\) and there is no other person \(C\) who is psychologically continuous with \(A\) at \(t_2\).
only x and y principle
Whether a later individual, \(y\), is numerical identical to an earlier individual, \(x\), only depends upon facts about \(x\) and \(y\) and the relations between them (it does not depend upon facts about some other individual \(c\))..
Examples
“If all the possible answers are implausible, it is hard to decide which of them is true, and hard even to keep the belief that one of them must be true. If we give up this belief, as I think we should, these problems disappear.”
Many unsolved problems:
“If all the possible answers are implausible, it is hard to decide which of them is true, and hard even to keep the belief that one of them must be true. If we give up this belief, as I think we should, these problems disappear.”
Yes, all problems “go away” if you just ignore them.
No solution vs. solution exists but it is not known.
Some people say that
OK, but
Claim is that reduplication is impossible.
Order we discussed theories:
flowchart LR
S(Soul)
Phy[Physical]
Psy[Psychological]
S ==> Phy
Phy ==> Psy
Where to go now?
flowchart LR
S(Soul)
Phy[Physical]
Psy[Psychological]
New["New theory?"]
Up["Give up"]
S ==> Phy
Phy ==> Psy
Psy ==> Phy
Psy ==> S
Psy ==> New
Psy ==> Up
Exercise
Is there a solution to the teletransportation problem?